C program to swap two numbers without using temporary variable(method 2)

Swapping is used in sorting algorithms like in bubble sort,that is when we wish to arrange numbers in a particular order either in ascending order or in descending order.

Problem:

Given two numbers num1=a and num2=b, task is exchange values of these numbers i.e num1=b and num2=a;

Method 2: Without using third variable

#include<stdio.h>

int main(){

    int num1=10,num2=20;

    void swapWithoutTemp (int,int);  //function prototype

   printf("Values before swapping by call by value: num1=%d,num2=%d.\n",num1,num2);

    swapWithoutTemp (num1,num2);     

    return 0;

}

//function definition : without using third variable

void swapWithoutTemp(int n1,int n2){

  n1=n1+n2;

  n2=n1-n2;

  n1=n1-n2;

  printf("Inside swap2 : num1=%d,num2=%d\n",n1,n2);

}

Output:

Please comment if you find anything incorrect, or you want to improve the topic discussed above.